fix 修复 excel合并注解会根据第一列合并的结果来决定后续的列合并

This commit is contained in:
Simple 2023-11-29 15:37:01 +08:00
parent 183e39f1cd
commit 3e85520c0f

View File

@ -93,14 +93,28 @@ public class CellMergeStrategy extends AbstractMergeStrategy {
// 空值跳过不合并
continue;
}
if (!cellValue.equals(val)) {
if (i - repeatCell.getCurrent() > 1) {
cellList.add(new CellRangeAddress(repeatCell.getCurrent() + rowIndex, i + rowIndex - 1, colNum, colNum));
if (j == 0) {
if (!cellValue.equals(val)) {
if (i - repeatCell.getCurrent() > 1) {
cellList.add(new CellRangeAddress(repeatCell.getCurrent() + rowIndex, i + rowIndex - 1, colNum, colNum));
}
map.put(field, new RepeatCell(val, i));
} else if (i == list.size() - 1) {
if (i > repeatCell.getCurrent()) {
cellList.add(new CellRangeAddress(repeatCell.getCurrent() + rowIndex, i + rowIndex, colNum, colNum));
}
}
map.put(field, new RepeatCell(val, i));
} else if (i == list.size() - 1) {
if (i > repeatCell.getCurrent()) {
cellList.add(new CellRangeAddress(repeatCell.getCurrent() + rowIndex, i + rowIndex, colNum, colNum));
} else {
RepeatCell firstCell = map.get(mergeFields.get(0));
if (repeatCell.getCurrent() != firstCell.getCurrent()) {
if (i - repeatCell.getCurrent() > 1) {
cellList.add(new CellRangeAddress(repeatCell.getCurrent() + rowIndex, i + rowIndex - 1, colNum, colNum));
}
map.put(field, new RepeatCell(val, i));
} else if (i == list.size() - 1) {
if (i > repeatCell.getCurrent()) {
cellList.add(new CellRangeAddress(repeatCell.getCurrent() + rowIndex, i + rowIndex, colNum, colNum));
}
}
}
}